👤
Vasileio3
a fost răspuns

6n+1+2m+1x3n+2-2n+2x3n+1 supra2nx3n+1-2n3n+2n+3n e NR NAT
nu-mi dati direct raspunsul!

Răspuns :

[tex] \frac{6n+1+2n+1*3n+2-2n+2*3n+1}{2n*3n+1-2n*3n+2n+3n} = \frac{6n+1+3n+2+6n+1}{1+5n} = \frac{(6+3+6)n+3+1}{1+5n} = \frac{15n+4}{1+5n} [/tex]

Succes.

Alte intrebari