Răspuns :
4x²+5x-4=0
x(4x+5)-4=0
x=0
4x+5-4=0
4x+1=0
4x=-1
x=-0.25
S={-0.25;0}
Sper ca te-am ajutat!
x(4x+5)-4=0
x=0
4x+5-4=0
4x+1=0
4x=-1
x=-0.25
S={-0.25;0}
Sper ca te-am ajutat!
V=radical
DELTA=25+64=89
x1;2=(-5+/-V89)/8
4x^2+5x-4=4[x-(-5+V89)/8][x-(-5-V89)/8]=[2x+(5-V89)/4][2x+(5+V89)/4]
DELTA=25+64=89
x1;2=(-5+/-V89)/8
4x^2+5x-4=4[x-(-5+V89)/8][x-(-5-V89)/8]=[2x+(5-V89)/4][2x+(5+V89)/4]