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[4,5+5,(6)]:0,61+13 intregi si 1 pe 3

Răspuns :

Renatemambouko
[4,5+5,(6)]:0,61+13 intregi si 1/3 =
=[45/10+(56-5)/9]:61/100+40/3 =
=(9/2+51/9):61/100+40/3 =
=(9/2+17/3):61/100+40/3 =
=(27+34)/6 × 100/61+40/3 =
=61/6 × 100/61+40/3 =
=100/6+40/3 =
=50/3+40/3 =
=90/3=30

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