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Liceac2017
a fost răspuns

cos60+[tex] \frac{1}{3} [/tex]*tg30*sin30=

Răspuns :

[tex]= \frac{1}{2}+ \frac{1}{3}* \frac{ \sqrt{3} }{3}* \frac{1}{2}= \frac{9+ \sqrt{3} }{18} [/tex]