Răspuns :
a+b+c=390
c=b+25
a=c+40=b+25+40
b+2b+25+25+40=390
3b=390-90
b=300:3
b=100
c=100+25=125
a=125+40=165
c=b+25
a=c+40=b+25+40
b+2b+25+25+40=390
3b=390-90
b=300:3
b=100
c=100+25=125
a=125+40=165
a+b+c=390
c=b+25⇒b=c-25=125-25=100
c=a-40⇒a=c+40=125+40=165
Inlocuim in relatie si obtinem:
c+40+c-25+c=390
3c+15=390
3c=375
c=125
Succes:<3
c=b+25⇒b=c-25=125-25=100
c=a-40⇒a=c+40=125+40=165
Inlocuim in relatie si obtinem:
c+40+c-25+c=390
3c+15=390
3c=375
c=125
Succes:<3