C6H6 + 3HNO3 => C6H3N3O6 + H2O
n c6h6 = 42.6 kg/ 78 kg/kmol = 0.55 kmol.
1 kmol c6h6 .... 3kmol HNO3
0.55 kmol c6h6...x kmol HNO3
x= 1.65 kmol HNO3 (cant. stoichiometric necesara)
y= 1.65 kmol + (10/100 * 1.65) = 1.815 kmol (cantitatea necesara + exces)
m HNO3 = 114.345 kg HNO3
%masice= m compus/masa amestesc
35=114.345/masa amestesc x100
masa amestec= 114.345 x 100/35 =326.7 kg amestesc
m H2SO4= 60/100 x 326.7 = 196.02 kg
m h2O = 0.05 * 326.7 = 16.335 kg