Fie a,b,c cele 3 numere
a + b + c = 92
a = 2×b
c = a:2-8 => a=2×c +16
a ______ ______+16
b ______+8
c ______
avem 4 segmente egale +8+16 = 92
92 -24=68
68 : 4 =17 (un segment)
a = 2 × 17+16=34+16=50
b = 17+8=25
c = 17
verificare : 50 + 25+ 17 = 92
a = 50
b = 25
c = 17
