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Eugenpopa35
a fost răspuns

Descompuneti in factori expresia: x la a douasprezecea -2x la a sasea+1

Răspuns :

[tex]( x^{12}-2x^6+1)=(x^6-1)^2=[tex][(x^3-1)(x^3+1)]^2=[(x-1)( x^{2} +x+1)(x+1)( x^{2} -x+1)]^2= \\= (x-1)^2(x+1)^2( x^{2} +x+1)^2( x^{2} -x+1)^2[/tex]

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