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Cine ma ajuta si pe mine la exercițiu va rog???

Cine Ma Ajuta Si Pe Mine La Exercițiu Va Rog class=

Răspuns :

Camela
a)(2/3)^3×(2/3)^4=(2/3)^(3+4)=(2/3)^7
b)(1/2)^4×(1/2)^3×(1/2)^1=(1/2)^(4+3+1)=(1/2)^8
c)(2 într. 1/3)^5:(7/3)^2=(2×3+1/3)^5:(7/3)^2=(7/3)^5:(7/3)^2=(7/3)^(5-2)=(7/3)^3
e)[(5/3)^2]^3=(5/3)^(2×3)=(5/3)^6

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