👤
a fost răspuns

[tex] \frac{1}{2} log_{2}( x^{2}+x+2)- log_{2}(3x-2)=1 [/tex]

Răspuns :

[tex] \sqrt{x^2+x+2} =2*(3x-2) \\x\ \textgreater \ \frac{2}{3} \\ x^{2} +x+2=12x-8 \\ x^{2} -11x+10=0 \\ x_{1}=1; x_{2}=10 [/tex]