a+b+c = 1 116
a:b = 5 => a= 5×b
c:b = 4 rest 16
c = 4×b + 16
a ______ ______ ______ ______ _____
b ______
c ______ ______ ______ ______+16
avem 10 segmente egale+16 = 1 116
1 116-16 = 1 100
1 100 : 10 = 110 (un segment)
a = 110 × 5 = 550
b = 110
c = 110 × 4 + 16 = 440 + 16 = 456
proba:
a+b+c = 550+110+456 = 1 116