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a fost răspuns

rezolvati in RxR,prin metoda substitutie,sistemulde ecuati
x+2y=3
0,2x-3,5y=4


Răspuns :

AndraI
[tex] \left \{ {{x+2y=3} \atop {0,2x-3,5y=4}} \right. [/tex] ⇒ [tex] \left \{ {{x=3-2y} \atop {0,2(3-2y)-3,5y}=4} \right. [/tex] ⇒ [tex] \left \{ {{x=3-2y} \atop {0,6-0,4y-3,5y=4}} \right. [/tex] ⇒[tex] \left \{ {{x=3-2y} \atop {-3,9y=4-0,6}} \right. [/tex] ⇒[tex] \left \{ {{x=3-2y} \atop {-3,9y=3,4}} \right. [/tex]⇒[tex] \left \{ {{x=3-2y} \atop {y= \frac{3,4}{-3,9}=-1,147 }} \right. [/tex]⇒[tex] \left \{ {{x=3-2*(-1,147)} \atop {y=-1,147}} \right. [/tex]⇒[tex] \left \{ {{x=5,294} \atop {y=-1,147}} \right. [/tex]