a,b,c numerele
a+b+c=1 556
b:2 = a:2+159 |×2 =>b =a+159×2 =>b = a+318
b:2 = c:2-46 |×2 =>b= c-46×2 =>b = c-92
b = c-92 =>c = b+92
a _____
b _____+318
c _____+92+318
avem 3 segmente egale+318+92+318
2×318+92 = 636+92 = 728
1 556-728 = 828
828:3 = 276 (un segment)
a = 276
b = 276+318 = 594
c = 276+92+318 = 686
V. 276+594+686= 1 556
