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E(x)=(x+4(3x-2)-3(x+1)²+11/4x³(x+1):1/x²(x+1)

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Răspuns :

Sobolan007
E(x)={[(x+4)(3x-2)-3(x+1)² +11 ]/4x³(x+1) }: 1/x²(x+1)
E(x)={[(3x²+12x-2x-8)-3(x²+2x+1) +11]/4x³(x+1)} · x²(x+1)/1
E(x)=(3x²+12x-2x-8-3x²-6x-3 +11) /4x
E(x)=(4x-11 +11) /4x
E(x)=4x /4x
E(x)=1

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