Răspuns :
2la puterea x² -4x= 32
2la puterea x² -4x= 32
x²-4x=32
x²-4x-32=0
Δ=(-4)²-4×(-32)=16+128=144
x₁=(4+√144)/2=(4+12)/2=8
x₂=(4-√144)/2=(4-12)/2=-4
2la puterea x² -4x= 32
x²-4x=32
x²-4x-32=0
Δ=(-4)²-4×(-32)=16+128=144
x₁=(4+√144)/2=(4+12)/2=8
x₂=(4-√144)/2=(4-12)/2=-4
2ˣ²⁻⁴ˣ= 32
2ˣ²⁻⁴ˣ= 2⁵
x²-4x= 5
x²-4x-5=0
(x-5)(x+1)= 0
x₁= -1
x₂= 5
Doamne ajuta!
2ˣ²⁻⁴ˣ= 2⁵
x²-4x= 5
x²-4x-5=0
(x-5)(x+1)= 0
x₁= -1
x₂= 5
Doamne ajuta!