-deduc masa molara a hidrocarburii
n=m/M
0,16=6,4/m----> M= 40g/mol
-deduc moli C din hidrocarbura
n,hidroc= V/Vm=> n= 4,928l/22,4l/mol=0,22mol
nCO2=nC= 29,04g/44g/mol= 0,66mol
0,22 mol.hidrocarbura ...............0,66 molCo2(=molC)
1mol.............................................................x
x=3molC
-hidrocarbura poate fi : C3H8, C3H6, C3H4
C3H4 are masa molara 40g/mol !!!!
