Răspuns :
Probalitatea=nr cazurilor favorabile/nr cazurilor posibile
1-20=10 nr pare; 10 nr impare
a) 10/20= 1/2
b) nr multiple de 3: 3,6,9,12,15,18
P=6/20= 3/10
c) pătrate perfecte: 1,4,9,16
P=4/20=1/5
Sper că te-am ajutat!
1-20=10 nr pare; 10 nr impare
a) 10/20= 1/2
b) nr multiple de 3: 3,6,9,12,15,18
P=6/20= 3/10
c) pătrate perfecte: 1,4,9,16
P=4/20=1/5
Sper că te-am ajutat!
1;2;3;4;5;6;7;8;9;10;11;12;13;14;15;16;17;18;19;20
din care:
a) P(E) = 10/20 = 1/2 = 50 % ;
b) P(E) = 6/20 = 3/10 = 30 % ;
c) P(E) = 4/20 = 1/5 = 20 % ;
din care:
a) P(E) = 10/20 = 1/2 = 50 % ;
b) P(E) = 6/20 = 3/10 = 30 % ;
c) P(E) = 4/20 = 1/5 = 20 % ;