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Calculati:a)3/x+2+7/x+2= b)3x-2/12+5x+2/12= c)4x-3/2x+x+2/x= d)x-2/xla2+x+2/x= e)x+2/y×7yla3/xla2-4=<br />f)(x/9-3x/2-x/10)÷x/20=<br />g)4x/xla2-4÷8xla2/x+2=<br />h)(x+2/xla2-3x-x-2/xla2+3x)÷25xla2/xla2-9=<br />i)[(x/x+1-xla2/xla2+2x+1)]×x+1/xla2=<br /><br />

Răspuns :

Vali208
a) 3/x+2+7/x+2=3/x+4+7/x=3+4x+7/(totul pe)x= 10+4x/(totul pe) x
b) 3x-2/12+5x+2/12=(3+5)x=8x
c)4x-3/2x+x+2/x=5x-3/2x+2/x=10x^(la putere)2-3+4/(totul pe)2x=10^2+1/(totul pe)2x
d)x-2/x^2+x+2/x=2x-2/x^2+2/x=2x^3-2+2x/(totul pe)x^2

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