👤
a fost răspuns

Va rogg am nevoie de ajutor la ex 13 dau coronita si ma abonezzz

Va Rogg Am Nevoie De Ajutor La Ex 13 Dau Coronita Si Ma Abonezzz class=

Răspuns :

[tex]\displaystyle \left\{ \frac{8}{35}+ \left[\left( \frac{3}{2} - \frac{33}{35} \right)+\left( \frac{3}{14} - \frac{2}{35} \right)-\left(2- \frac{12}{7} + \frac{5}{14} \right)\right]\right\} \cdot 3 \frac{1}{3} =\\ \\ =\left[ \frac{8}{35} + \left( \frac{105-66}{70} + \frac{15-4}{70} - \frac{28-24+5}{14} \right)\right] \cdot \frac{10}{3} =[/tex]
[tex]\displaystyle =\left[ \frac{8}{35} + \left( \frac{39}{70} + \frac{11}{70} - \frac{9}{14} \right)\right] \cdot \frac{10}{3}=\left( \frac{8}{35} + \frac{39+11-45}{70} \right) \cdot \frac{10}{3} = \\ \\ =\left( \frac{8}{35} + \frac{5}{70} \right) \cdot \frac{10}{3} = \frac{16+5}{70} \cdot \frac{10}{3} = \frac{21}{70} \cdot \frac{10}{3} =1[/tex]