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a fost răspuns

2intreg si 3 cincimi de impartit la 6 intreg si o 15 plus o septime minus 1 intreg si 39 pe 73= rog frumos un raspuns

Răspuns :

Rapunzel15
2intreg3/5=2×5+3/5=13/5
1 intreg39/73=73×1+39/73=112/73
6 intreg1/5 =6×5+1/5=31/5
13/5:31/5+1/7-112/73 =13/5×5/31+1/7-112/73=
=13/31+1/7-112/73=
=13×7×73/15841+73×31/15841-112×31×7/15841=
=6643+2263-24304/15841=
= nu e in regula cu datele problemei

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