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Radical 3(2 radical2-3 radical3)-radical2(2radical3-3 radical 2)

Răspuns :

[tex]\displaystyle \sqrt{3} \left(2 \sqrt{2} -3 \sqrt{3} \right)- \sqrt{2} \left(2 \sqrt{3} -3 \sqrt{2} \right)=2 \sqrt{6} -3 \cdot 3-2 \sqrt{6} +3 \cdot 2= \\ \\ =2 \sqrt{6} -9-2 \sqrt{6} +6=-9+6=-3[/tex]

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