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a fost răspuns

descompuneti in factori:
1) x²+6x+9-4y²=
2) x²+4x+4-y²-2y-1=
3) x²+14x+49-5(x+7)=
4)(x+2)(2x-1)²-4x-8=

Răspuns :

1) x²+6x+9-4y²=x(x+6)+(3-2y)(3+2y)
2) x²+4x+4-y²-2y-1=(x+2)²-(y+1)²
3) x²+14x+49-5(x+7)=x²+14x+49-5x-35=x²+11x+14
4)(x+2)(2x-1)²-4x-8=(x+2)(2x-1)²-4(x+2)=(x+2)(4x²-4x+1-4)=(x+2)(4x²-4x-3)

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