Mdanut28 Mdanut28 18-01-2017 Matematică a fost răspuns [tex] \sqrt{3} x ( \sqrt{3} + \frac{ \sqrt{3} }{3} ) - \sqrt{3} y ( 2 \sqrt{3} - \frac{2 \sqrt{3} }{3} )+ 6y-3x= [/tex]
