Răspuns :
A={x∈N|[tex] 2^{x} [/tex]+1≤16}
Incepem sa-i dam valori lui x:
[tex] 2^{0} [/tex]+1≤16 (A)
[tex] 2^{1} [/tex]+1≤16 (A)
[tex] 2^{2} [/tex]+1≤16 (A)
[tex] 2^{3} [/tex]+1≤16 (A)
[tex] 2^{4} [/tex]+1≤16 (F)
A={0,1,2,3}
Incepem sa-i dam valori lui x:
[tex] 2^{0} [/tex]+1≤16 (A)
[tex] 2^{1} [/tex]+1≤16 (A)
[tex] 2^{2} [/tex]+1≤16 (A)
[tex] 2^{3} [/tex]+1≤16 (A)
[tex] 2^{4} [/tex]+1≤16 (F)
A={0,1,2,3}