[tex]1)M_{O_2}=2A_{O}=32g/mol[/tex]
[tex]n=\frac{m}{M}=20[/tex]
[tex]1mol \ O_2..........22,4l[/tex]
[tex]20moli \ O_2..........x \ l[/tex]
[tex]x=20*22,4=448l[/tex]
[tex]2)M_{Ag}=108g/mol[/tex]
[tex]M_{Al}=27g/mol[/tex]
[tex]n_{Ag}=\frac{m_{Ag}}{M_{Ag}}=0,2[/tex]
[tex]n_{Al}=\frac{m_{Al}}{M_{Al}}=0,3[/tex]
[tex]\frac{0,3}{0,2}=1,5[/tex]
