carbonat de sodiu = Na2CO3
raport atomic = Na : C : O = 2 : 1 : 3
raport de masa = 2 x 23 + 12 + 3 x 16 = 55 + 48 = 98 g per mol
compozitia: 98g Na2CO3 ............ 46g Na ........ 12g C ......... 48g O2
100g Na2CO3 ............ xg Na ........... yg C ........... zg O2
x = 100x46/98= 49, 938% Na
y = 100x12/98= 12, 244% C
z = 100x48/98= 48, 979% O2
carbonat de potasiu: K2CO3
r.a.: 2:1:3
r.m.: 2x39 + 12 + 3x16 = 138 g per mol
compozitia: in 138g K2CO3................... 78g K ............ 12g C.......... 48 g O2
in 100 g K2CO3...................xg K.................yg C.............. xg O2
x= 100x78/138=56,5217 % K
y= 100x12/138= 8, 6956 % C
z= 100x48/138= 34, 7826 % O2
carbonul de bor= B2(CO3)3
r.a.= 2:3:9
r.m= 2x10 + 3x12 + 9x16 = 200
rezulta compozitia % = 10% B , 18%C, 72% O2
