Notam numerele de aflat cu a, b si c.
Transcriem datele problemei si obtinem:
(a+b):2=9⇒a+b=9x2⇒a+b=18 (1)
(a+c):2=33⇒a+c=33x2⇒a+c=66⇒a=66-c (2)
(b+c):2=40⇒⇒b+c=40x2⇒b+c=80⇒b=80-c (3)
Inlocuim relatiile 2 si 3 in relatia 1 si obtinem:
66-c+80-c=18
146-2c=18
146-18=2c
2c=128
c=64
Ceea ce inseamna ca:
a=66-c
a=66-64
a=2
b=80-c
b=80-64
b=16
Concluzie a=2, b=16 si c=64
