Mai intai introduci intregii in fractie.
5 3/5=(5x5+3)/5=28/5
1 1/3=(1x3+1)/3=4/3
7 7/12=(7x12+7)/12=91/12
2 1/4=(2x4+1)/4=9/4
Transcriem exercitiul:
(28/5+4/3):(91/12-9/4), aducem la acelasi numitor fiecare paranteza
[(28x3+4x5)/15]:[(91+9x3)]/12
[(84+20)]/15]:[(91+27)]/12
(104/15):(118/12)
(104/15)x(12/118), simplificam cu 3 si 4
104/5x1/27=104/135
