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a fost răspuns

9.calculati:d)2 intreg 1 supra 4x2 supra 15+8 supra 15;e)17 supra 9-4 supra 27x3 intreg 15 supra 16,dau coroana!

Răspuns :

[tex]2 \frac{1}{4} * \frac{2}{15} + \frac{8}{15} = \frac{9}{4} * \frac{2}{15} + \frac{8}{15} = \frac{3}{10} + \frac{8}{15}= \frac{18}{30} + \frac{16}{30} = \frac{5}{6}  [/tex]
[tex] \frac{17}{9} - \frac{4}{27} *3 \frac{15}{16} = \frac{17}{9} -\frac{1}{3} * \frac{7}{4} =\frac{17}{9} - \frac{7}{12} = \frac{68}{36} - \frac{21}{36} =\frac{47}{36}[/tex]
Renatemambouko
d)2 intreg 1/4x2/15+8/15=
=9/4x2/15+8/15=
=3/2x1/5+8/15=
=3/10+8/15=
=(9+16)/30=
=25/30
=5/6=
=0,8(3)
e)17/9-4/27x3 intreg 15/16=
=17/9-4/27x63/16=
=17/9-1/3x7/4=
=17/9-7/12
=(68-21)/36=
=47/36=
=1,30(5)



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