a) 2+2^2+2^3=6^6
b) 3^3-3^2-3=0^0
c) 2×2^2×2^3=2^6
d)3^3:3^2:3=3^0
e) 1^0+0^1+0^245+1^2009+2009^0=
=1+0+1+1+0=3
f) [3^2-(16-2×2^2)+4×3^2-5^2]-5^0=
=[9-(16-2^3)+4×9-25]-1=
=[9-(16-8)+36-25]-1=
=(9-8+36-25)-1=
=(1+36-25)-1=
=(37-25)-1=
=12-1=11
Sper ca e corect si ca am ajutat!
