-calculez n(niu) H2, din ecuatia de stare a gazelor
pV= nRT
15x5= nx0,082x(273+30)------> n= 3,02molH2
- deduc moli si masa de HCl din ecuatia
2mol..............................1mol
2HCl + Zn---> ZnCl2 + H2
x.......................................3,02mol
x= 6,04mol HCl
m= nxM--> m= 6,04mol(1gH+35,5gCl)g/mol= 220g
-calculez masa de solutie ce contine dizolvate 220g HCl
c/100= md/ms---> 22/100= 220/ms----------------> calculeaza ms !!!
