Răspuns :
problema 1
dinu 6 masinute
traian 6x2=12 masinute
ionut 6x3=18 masiute
6+12+18=36 de masinute in total
problema 2
Alex are 2 mere
mama ii da 2x2=4 mere
bunica ii da 5x4=20 mere
acum Alex are 2+4+20=26 mere
ii da surorii sale 10 mere
Alex ramane cu 26-10=16 mere
dinu 6 masinute
traian 6x2=12 masinute
ionut 6x3=18 masiute
6+12+18=36 de masinute in total
problema 2
Alex are 2 mere
mama ii da 2x2=4 mere
bunica ii da 5x4=20 mere
acum Alex are 2+4+20=26 mere
ii da surorii sale 10 mere
Alex ramane cu 26-10=16 mere
Problema 1) Dinu are 6 masinute Traian 6×2= 12 masinute. Ionut 6×3= 18 masinuti, 6+12+18= 36 de masinute total.Problema 2) Alex are doua mere, mami li da 2×2=4 mere, bunica li da 5×4= 20 mere acum.Alex are2+4+20 =26 mere li da surori sale 10 mere Alex ramane cu 26-10= 16 mere.