Răspuns :
a+b+b+c=17
c=2a
b-1=a⇒b=a+1
inlocuim in prima relatie pe "b" si "c" cu valorile obtinute si obtinem:
a+a+1+a+1+2a=17
5a+2=17
5a=17-2
5a=15
a=15:5
a=3
c=2a=2x3=6
b=a+1=3+1=4
Proba: a+b+b+c=3+4+4+6=17
c=2a
b-1=a⇒b=a+1
inlocuim in prima relatie pe "b" si "c" cu valorile obtinute si obtinem:
a+a+1+a+1+2a=17
5a+2=17
5a=17-2
5a=15
a=15:5
a=3
c=2a=2x3=6
b=a+1=3+1=4
Proba: a+b+b+c=3+4+4+6=17
a+b+b+c=17
C=20
b-1=a=>b=a+1
b+a+1+a+1+2a=17
5a=17-2
5a=15
5a=15:5
a=3
C=2a=2x3=6
B=6+1=3+1=4
C=20
b-1=a=>b=a+1
b+a+1+a+1+2a=17
5a=17-2
5a=15
5a=15:5
a=3
C=2a=2x3=6
B=6+1=3+1=4