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Calculati:(2x+3)²-3x(1-x)+2(x+3)(x-3)-(3x-2)².

Dau coronita !!!

Răspuns :

Dariageorgi9876
sper ca te-am ajutat :) :) :)
Vezi imaginea Dariageorgi9876
MadalinaMadutaa
[tex](2x+3)^2-3x(1-x)+2(x+3)(x-3)-(3x-2)^2=\\\\ (2x)^2+2*2x*3+3^2-3x+3x^2+2(x^2-3^2)-(3x)^2+2*3x*2-2^2\\\\ =4x^2+12x+9-3x+3x^2+2x^2-18-9x^2+12x-4\\\\ =(4x^2+3x^2+2x^2-9x^2)+(12x-3x+12x)+(9-18-4)\\\\ =0+21x-13\\\\ =21x-13[/tex]

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