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Denisa732
a fost răspuns

Cum se rezolva aceaste ecuați : -3 (x+2)-4=3-(x+2)-9 , (6x-5) (2x+1)-12x la a2 =0 va rog ajutati-ma..

Răspuns :

Nitugheorghe57
-3(x+2)-4=3-(x+2)-9⇒-3x-6-4=3-x-2-9⇒
-3x-10=-x-8⇒-3x+x=10-8⇒-2x=2⇒x=-2|2⇒x=-1

b)(6x-5)(2x+1)-12x²=0⇒12x²+6x-10x-5-12x²=0⇒
-4x-5=0⇒-4x=5⇒x=-5|4
succes
-3(x+2)-4=3-(x+2)-9
-3x-6-4=3-x-2-9
-3x-10=-x-8
-3x+x=10-8
-2x=2
 x=-1

(6x-5)(2x+1)-12x²=0
12x²+6x-10x-5-12x²=0 
-4x-5=0
-4x=5
x=-5/4 x=-1.25
Sper ca ai inteles!!!