1b
h=80/(10×4)=2 m
1c
40000 l= 40 m³
hapa=40/(10×4)=1 m
lungime tija=√(10²+4²+1)=√117≈10,82
2b
sin B=12/24=1/2
m(∡B)=30°
2c
AC=√(24²-12²)=√432=12√3 cm
ducem CD bisectoarea unghiului C
teorema bisectoarei
AD/DB=AC/CB=12/24=1/2
DB=2AD
AB=AD+DB=AD+2AD=3AD
AD=12√3 :3=4√3 cm
CD=√[12²+(4√3)²]=√(144+48)=√192=8√3 cm
