👤
Raduionita
a fost răspuns

Mini Evaluare "Dau 60 Puncte"
Ecuatii de gradul 1 cu o necunoscuta
Ex.1 stabiliti daca ecuatiile sint echivalente
b)x=1 si6x+6=0 c)-3x+2x=4 si 2(x+4)=0; d) [tex] \frac{1}{5} [/tex] x-2=0 si 2x+2x=40;
e)[tex] \sqrt{3} [/tex] = -x si 2x+2[tex] \sqrt{3} [/tex] =0; f)lxl =4 si 2x=8; g) [tex] x^{2} [/tex] =9 si x= -3


Ex.4 Determinati a ∈ R, astfel ca -1 sa fie solutie a ecuatiei cu necunoscuta x ∈ R:
a)3x-1=3x+a; b)[tex] \sqrt{3} [/tex] -2a=x+3.


Ex.5 Rezolvati ecuatiile:
a)2(x+1)=8,x∈N; b)3(x+2)=2x+5,x∈Z; c)5(2x-4)=3(4x+2),x∈Z; d)2(3x-1,6)-3=2x+1,x∈Q: e)-4(x+[tex] \sqrt{2} [/tex] )-3(x+[tex] \sqrt{2} [/tex] )= -11x+2[tex]\sqrt{2} [/tex] ,x∈R; f)0,5(x-2)=3x+4 (x-[tex] \frac{1}{2} [/tex] ) ,x∈R.



Ex.6 Rezolvati in multimea R ecuatiile:
a)3x+5=2; b)3x-8=5-7x; c)3x-[tex] \frac{1}{2} [/tex] =[tex] \frac{3}{2} [/tex] ; d)5x - [tex] \frac{4}{3} [/tex] =7; e)3x+[tex] \frac{7}{2} [/tex] = [tex] \frac{3}{2} [/tex] ; f) x+1=2(x-1); g) 3(x-2)-4(x-1)= -7(x+2); h)2[tex] \sqrt{2} [/tex] x +3=2x+3[tex] \sqrt{2} [/tex].