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Calculeaza,impartind fiecare termen al sumei la impartitor
a) (21+14+35):7
b) (16+20+32):4
c) (35+45+30):5


Rezolva,dupa model:
(24:6)+(30:6)=(24+30):6=54:6=9

a) (25:5)+(15:5)= b) (42:7)+(14:7=
(40:8)+(32:8)= (16:4)+(24:4=

Răspuns :

Justme210
a)  (25 + 15):5 = 40 : 5 = 8

b) (42 + 14) : 7 = 56 : 7 = 8

c) (40 + 32) : 8 = 72 : 8 =9

d) (16 + 24) : 4 = 40 : 4 = 10
Sanduurzica
1)
a) (21+14+35):7=21:7+14:7+35:7=3+2+5=10
b) (16+20+32):4=16:4+20:4+32+4=4+5+8=17
c) (35+45+30):5=35:5+45:5+30:5=7+9+6=22
2)
a) (25:5)+(15:5)=(25+15):5=40:5=8
b) (42:7)+(14:7)=(42+14):7=56:7=8
c) (40:8)+(32:8)=(40+32):8=72:8=9
d) (16:4)+(24:4)=(16+24):4=40:4=10

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