a) Atotala =(60*40+50*40+60*50)*2=(2400+2000+3000)*2=14800 cm² b) V=60*40*50=120000 cm³ Vcubulet=10*10*10=1000 cm³ 120000:1000=120 cubulete deci in cutie nu incap 125 cubulete
c) pentru a afla distanta cea mai scurta intre A si C' consideram cubul desfasurat si aplicam Pitagora in triunghiul AC'C (latura AC=AB+BC=60+40=100 (care contine si punctul B) AC'=√(50²+100²)=√(2500+10000)=√12500=50√5
