Se dă:
L=b1+b2=4m
G1 = 300N
G2= 250N
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L-b1=L-b2 = ?
----------------Rezolvare
G=F
[tex] \frac{F1}{F2} = \frac{b2}{b1} \\
\frac{F1 }{F2} = \frac{300N}{250N} = 1,2 \\
\frac{b2}{b1} = 1,2 \\
b1+b2 = 4m \\
b1+ 1,2*b1 = 4m \\
b1*(1,2+1)=4m \\
b1*2,2=4m \\
b1= 4m/2,2 \\
b1= \frac{180}{99}m = \frac{20}{11} m \\
b2= 4m- \frac{20}{11}m = \frac{24}{11} m \\
Punctul de sprijin trebuie sa fie 20/11m distanta de la primul copil \\
sau/si 24/11m distanta de la al doilea copil[/tex]