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Georgiyougeo
a fost răspuns

1. a) Rezolvati ecuatia : ( x+1)+(x+2)+...(x+41)=40x+860
b) Efectuati calculele: √48:√3+5 supra√ 5• √10 .

Răspuns :

Renatemambouko
(x+1)+(x+2)+.....(x+41)=40x+860
x+1+x+2+x+3+....+x+41=40x+860
41x+(1+2+3...+41)=40x+860
41x+41(41+1)/2=40x+860
41x+861=40x+860
x=-1

√48:√3+5 /√ 5• √10=
(√48x√3)/3+√5 • √10= 4+5√2


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