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Efectuati:
c)12x/x[la 2]+1 - 8x/x[la 2]+1
d)4y[la3]/x-y[la 2] + 3xy+y[la 3]/y[la 2]-x
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Răspuns :

Renatemambouko
c)12x/(x²+1) - 8x/(x²+1)=
=12x - 8x/(x²+1)=
=4x/(x²+1)

d)4y³/(x-y²) + (3xy+y³)/(y²-x)=
=4y³/(x-y²) - (3xy+y³)/(x-y²)=
=(4y³-3xy-y³)/(x-y²) =
=(3y³-3xy)/(x-y²) =
=3y(y²-x)/(x-y²) =
=-3y

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