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Anuskame
a fost răspuns

Rezolvati,in multimea nr naturale,inecuatiile:

a) 7x-5 mai mic sau egal cu 2x+60

b) 18x+256>7*(2x+103)

c)12x+9 mai mic sau egal cu 4*(3x+2)

Răspuns :

7x-5≤2x+60
7x-2x≤60+5
5x≤65
x≤13
x∈{0,1...13}

18x+256>7(2x+103)
18x+256>14x+721
18x-14x>721-256
4x>465
x>116.25
x∈{117,118..+oo}

12x+9≤4(3x+2)
12x+9≤12x+8
12x-12x≤8-9
0≤ -1 (fals)

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