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Llidia123
a fost răspuns

1)Efectuati , respectand ordinea operatilor:
a)√3*3√2-5√6*4+4√3*2√2-4√2*3√3=..
b)√6+2√3*√3-2√2*3√3+2√2*5√2+√3*4√2+√3*√3=..
2)Aratati ca nr (-√48+√200) / (2√3+5√2) este rational.

Răspuns :

Renatemambouko
a)√3*3√2-5√6*4+4√3*2√2-4√2*3√3=
=3√6-20√6+8√6-12√6=
=11√6-32√6=
=-21√6

 b)√6+2√3*√3-2√2*3√3+2√2*5√2+√3*4√2+√3*√3=
=√6+6-6√6+20+4√6+3=
=29-√6

2)(-√48+√200) / (2√3+5√2)=
=(-4√3+10√2) / (2√3+5√2)=
=-2(2√3-5√2) / (2√3+5√2)=
=-2(2√3-5√2)(2√3-5√2) / (2√3+5√2)(2√3-5√2)=
=-2(36-20√6+100) / (12-50)=
=-2(36-20√6) / (-38)=
=(36-20√6) / 19













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