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Eliza109
a fost răspuns

Aflati x din: A) 2×{120-2×[(2×X+18)÷15+180]÷11}=200. B) 2010 la puterea 0+{2×[3+(X-2 la puterea 2)× 5 ])÷6×7=2 la puterea 3. Ajutati-ma si repede.

Răspuns :

Renatemambouko
a) 2×{120-2×[(2×X18)÷15+180]÷11}=200
120-2×[(2×X+18)÷15+180]÷11=100
-2×[(2×X+18)÷15+180]÷11=-20
(2×X+18)÷15+180=110
(2×X+18)÷15=110-180
(2×X+18)÷15=-70
2×X+18=-1050
2×X=-1068
x=-534

b) 2010⁰+{2×[3+(X-2²)× 5 ])÷6×7=2³
1+{2×[3+(X-2²)× 5 ])÷6×7=8
{2×[3+(X-2²)× 5 ])÷6=(8-1):7
{2×[3+(X-2²)× 5 ])÷6=1
2×[3+(X-2²)× 5 ]=6
3+(X-2²)× 5=3
(X-2²)× 5=0
X-2²=0
X=2²
X=4





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