👤
a fost răspuns

simplificati fractia 2^2005 -5x2^2000\2^1999 +2^2001 +2^2003

Răspuns :

(2^5×2^2000-5×2^2000)\(2^1999)(1+2^2+2^4)=(32×2^2000-5×2^2000)\(2^1999)(5+16)=(27×2^2000)\(21×2^1999)=27×2\21=9×2\7=18\7