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Vaseavasea1234565
a fost răspuns

Rezolva ecuatia 6sin² x-5sin x+1=0

Răspuns :

notam sinx=t 
6t²-5t+1=0
6t²-3t-2t+1=0
3t(2t-1)-(2t-1)=0
(2t-1)(3t-1)=0
2t-1=0⇒t₁=1/2
3t-1=0⇒t₂=1/3
sinx=1/2⇒x= 30 grade sau π/6 radiani
sin x=1/3 ⇒ x= arccos 1/3
Sper ca te-am ajutat.

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