x:6=c1 rest 4, x= 6c1+4= 6c1+6-2
x :8= c2 rest 6, x= 8c2+6= 8c2+8-2
adun 2 si obtin x+2=6*(c1+1)=8(c2+1) adica x+2 e multiplu comun al nr 6 si 8
6=2*3
8=2^3, rezulta [6,8]=2^3*3=24
x+2=M (24)
sunt mai multe solutii daca nu mi se spune nimic de nr x
x+2∈{24,48,72.....}
adica x∈{22,46,70......}
