[tex][0,(3)+1,(3):1\frac{7}{9}]:(1+\frac{1}{12})=\\
\\
{[\frac{3}{9}+1\frac{3}{9}:\frac{9+7}{9}]:\frac{12+1}{12}=}\\
\\
{[\frac{1}{3}+\frac{12}{9}\cdot \frac{9}{16}]\cdot \frac{12}{13}=}\\
\\
(\frac{1}{3}+\frac{3}{4})\cdot \frac{12}{13}=\\
\\
\frac{13}{12}\cdot \frac{12}{13}=\boxed{1}[/tex]
