V,H2= 1,12 L
n(niu)= V/Vm=1,12l/ 22,4l/mol=0,05molH2
din ecuatie, deduc moli si V metan
1mol.............................2mol
CH4-------------> C + 2H2
n...............................0,05mol
n=0,025molCH4
V= n x V,m---> V= 0,025molx 22,4l/mol= calculeaza !!!!